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Oraclerownum案例解说

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选择表中的某一行记录:(理解:rownum是oracle系统顺序分配为从查询返回的行的编号)select * from (select rownum a,t.* from te

选择表中的某一行记录:(理解:rownum是Oracle系统顺序分配为从查询返回的行的编号)
select * from (select rownum a,t.* from testtab t) where a=2;
select * from (select rownum a,t.* from testtab t) where a=3;
select * from (select rownum a,t.* from testtab t) where a=4;
不能为:
select * from (select rownum,t.* from testtab t) where rownum=2;或
select * from testtab where rownum=2;
返回多行记录:
select * from testtab where rownum<=10;
返回某段记录:(如取记录表中4-10行)
select * from (select rownum no,testtab.* from testtab where rownum<=10) where no>=4;
返回有条件且经过排序的某段记录:
select rownum num1,tt.* from
(select rownum num,t.* from
(select EcodeInfo.* from EcodeInfo where a=1 order by ecode desc) t) tt
where num>19 and rownum<20>
以为oracle是先提取记录再排序的,而oracle的rownum是在提取记录就已经生成,,它先于排序操作,所以必须使用子查询先排序。
不能为:
select * from tsettab where rownum>10;
返回最后一行记录:
select * from (select rownum a,t.* from testtab t) where a=(select count(*) from testtab);
返回最后N行记录:
select * from (select rownum a,t.* from testtab t) where a=(select count(*)-N from testtab);

----------------
select * from adminrole where rownum<=4
minus
select * from adminrole where rownum<2>

select * from
(select rownum row_id ,b.* from (select a.* from sorttable a order by sortid)b)
where row_id between 5 and 9;

linux

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